라이브러리 없이 mktime등 time함수 구현

AVR에서 필요해서 구현했습니다. 그래서 좀 type같은게 더럽(the love)습니다..하하...

tm을 epoch time 으로 변환하는건 만들었는데...

반대 상황은 또 언제 만들지...하하..ㅠㅠ

10분만에 만들었네요...ㅎ

최신 버전은

https://github.com/jic5760/jstime

을 확인해 주세요~

구현소스

/* * jstime.c * * Created: 2016-02-20 PM 11:54:05 (GMT+09:00) * Author: jichan (jic5760@naver.com) */ #include "jstime.h" /* MSVC(Visual Studio)에서는 inline가 작동하지 않기 때문 */ #ifdef _MSC_VER #define _JSTIME_INLINE static #else #define _JSTIME_INLINE inline #endif static const char _jstime_MonDays[2][12] = { {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}, {31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31} }; _JSTIME_INLINE int32_t _jstime_abs_sec(int32_t n) { if(n < 0) return 60+n; else return n; } _JSTIME_INLINE int32_t _jstime_abs_min(int32_t n) { if(n < 0) return 60+n; else return n; } _JSTIME_INLINE int32_t _jstime_abs_hour(int32_t n) { if(n < 0) return 24+n; else return n; } _JSTIME_INLINE void _jstime_monproc(int32_t *pyear, int32_t *pmon) { while(*pmon > 12) { *pmon -= 12; *pyear += 1; } while(*pmon <= 0) { *pmon += 12; *pyear -= 1; } } _JSTIME_INLINE char _jstime_isleapyear(int year) { return ((((year%4==0)&&(year%100!=0)) || (year%400==0)) ? 1 : 0); } _JSTIME_INLINE char _jstime_isleapyear_since1900(int year) { year += 1900; return ((((year%4==0)&&(year%100!=0)) || (year%400==0)) ? 1 : 0); } _JSTIME_INLINE void _jstime_dayproc(int32_t *pyear, int32_t *pmonth, int32_t *pday) { char mondays; if(*pday > 0) { while(*pday > (mondays = _jstime_MonDays[_jstime_isleapyear_since1900(*pyear)][*pmonth-1])) { *pmonth += 1; _jstime_monproc(pyear, pmonth); *pday -= mondays; } }else{ while(*pday <= 0) { *pmonth -= 1; _jstime_monproc(pyear, pmonth); mondays = _jstime_MonDays[_jstime_isleapyear_since1900(*pyear)][*pmonth-1]; *pday += mondays; } } } char jstime_isleapyear(int year) { return _jstime_isleapyear(year); } char jstime_isleapyear_since1900(int year) { return _jstime_isleapyear_since1900(year); } char jstime_mondays(char isleapyear, char month) { if(isleapyear < 0 || isleapyear > 1) return -1; if(month > 12 || month < 1) return -1; return _jstime_MonDays[isleapyear][month-1]; } int jstime_getydaysFromDate(int year, int month, int day) { unsigned char i; unsigned char j; int mday = 0; if(month > 12 || month < 1 || day < 1) return -1; if(_jstime_isleapyear(year)) { j = 1; }else{ j = 0; } if(_jstime_MonDays[j][month-1] < day) return -1; for(i=0; i<month-1; i++) { mday += _jstime_MonDays[j][i]; } mday += day; return mday; } int64_t jstime_gettimestamp(jstm_t *tm) { int16_t i, j; uint16_t NumberOfleapYears=0; uint16_t NumberOfNotleapYears=0; uint16_t NumberOfThisYearDates=0; int64_t TotalSec=0; uint8_t MonIndex; int32_t year = tm->tm_year;// + 1900; int32_t month = tm->tm_mon + 1; int32_t day = tm->tm_mday; int32_t hour = tm->tm_hour; int32_t min = tm->tm_min; int32_t sec = tm->tm_sec; min += sec/60; sec=_jstime_abs_sec(sec%60); hour += min/60; min=_jstime_abs_min(min%60); day += hour/24; hour=_jstime_abs_hour(hour%24); _jstime_monproc(&year, &month); _jstime_dayproc(&year, &month, &day); j=1900; for(i=year-1;i>=0;i--, j++) { if(_jstime_isleapyear(j)) NumberOfleapYears++; } NumberOfNotleapYears = year - NumberOfleapYears; //365 * 60*60*24 = 365 * 86400 = 31536000 //366 * 60*60*24 = 366 * 86400 = 31622400 TotalSec+=31536000LL*NumberOfNotleapYears; TotalSec+=31622400LL*NumberOfleapYears; if(_jstime_isleapyear_since1900(year)){ MonIndex=1; }else{ MonIndex=0; } for(i=0;i<(month-1);i++){ NumberOfThisYearDates+=(uint16_t)_jstime_MonDays[MonIndex][i]; } NumberOfThisYearDates+=(day-1); TotalSec+=NumberOfThisYearDates*86400; TotalSec+=hour * 3600; TotalSec+=min * 60; TotalSec+=sec; /* unix epoch time은 1970년부터 시작하므로 1900->1970년의 70년간 흐른 초를 더해줌 */ return TotalSec - 2208988800; } int jstime_gettm(int64_t timestamp, jstm_t *tm) { int32_t year = 0; int32_t month = 0; int32_t day = 0; int32_t hour = 0; int32_t min = 0; int32_t sec = 0; int32_t ydays = 0; char wday; int64_t tsdays; int32_t tstime; int32_t tmp; char isleapyear; tsdays = timestamp / 86400; tstime = timestamp % 86400; hour = tstime / 3600; tstime = tstime % 3600; min = tstime / 60; sec = tstime % 60; wday = (tsdays + 4) % 7; year = 1970; tmp = 0; do { tsdays -= tmp; if ((isleapyear = _jstime_isleapyear(year))) { tmp = 366; } else{ tmp = 365; } year++; } while (tsdays >= tmp); year -= 1; ydays = 0; month = 0; tmp = 0; do { tsdays -= tmp; ydays += tmp; tmp = _jstime_MonDays[isleapyear][month]; month++; } while (tsdays >= tmp); day = tsdays; ydays += day; tm->tm_year = year - 1900; tm->tm_mon = month - 1; tm->tm_mday = day + 1; tm->tm_hour = hour; tm->tm_min = min; tm->tm_sec = sec; tm->tm_yday = ydays; tm->tm_wday = wday; return 0; }

구현한 함수들

/* Leap year 체크 (year : 0년부터 시작한 년도) */ extern char jstime_isleapyear(int year); /* Leap year 체크 (year : 1900년부터 시작한 년도) */ extern char jstime_isleapyear_since1900(int year); /* 월별 날짜 수 (isleapyear : 0-no leap year / 1-leap year) */ extern char jstime_mondays(char isleapyear, char month); /* day of year 구하기 (year : 0년부터 시작한 년도) */ extern int jstime_getydaysFromDate(int year, int month, int day); /* epoch time 구하기 (1970년 1월 1일 0시 0분 0초 부터 흐른 초) */ extern int64_t jstime_gettimestamp(jstm_t *tm); /* timestamp을 tm으로 바꾸기 */ extern int jstime_gettm(int64_t timestamp, jstm_t *tm);

* 2016-06-01 수정

매월 1일 또는 매년 1일, month/year가 이전달로 나오며 days/month가 이전달 마지막 날/달+1 으로 출력되는 문제 해결.

예) ts:1464762600 (2016-06-01 6:30:00) -> 2016-05-32 06:30:00

ts:1451606400 (2016-01-01 0:0:0) -> 2015-13-01 0:0:0

} while (tsdays > tmp);

을

} while (tsdays >= tmp);

으로 수정함.